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$$\begin{gathered} ∆d_{S_1}>∆d_{M\text{'}}>∆d_M \\ \Rightarrow \frac{\sqrt{S_1{S_2}^2+M{S_1}^2}-M{S}_1}{\lambda }<k+\frac{{\phi }_2-{\phi }_1}{2\pi }+0,5<\frac{-S_1{S}_2}{\lambda } (\perp S_1) \\ \frac{-S_1{S}_2}{\lambda }<k+\frac{{\phi }_2-{\phi }_1}{2\pi }+0,5<\frac{M{S}_2-\sqrt{S_1{S_2}^2+M{S_2}^2}}{\lambda } (\perp S_2) \end{gathered}$$

$$\begin{gathered} ∆d_{S_1}>∆d_{M\text{'}}>∆d_M \\ \Rightarrow \frac{\sqrt{S_1{S_2}^2+M{S_1}^2}-M{S}_1}{\lambda }<k+\frac{{\phi }_2-{\phi }_1}{2\pi }<\frac{-S_1{S}_2}{\lambda } (\perp S_1) \\ \frac{-S_1{S}_2}{\lambda }<k+\frac{{\phi }_2-{\phi }_1}{2\pi }<\frac{M{S}_2-\sqrt{S_1{S_2}^2+M{S_2}^2}}{\lambda } (\perp S_2) \end{gathered}$$

$$\begin{gathered} X\mathrm{é}t \cos \left(\frac{∆\phi }{2}\right): \Rightarrow k \\ \Rightarrow I{O}_{min}=\sqrt{{\left(\lambda k_{min}\right)}^2-\frac{l^2}{4} },I{O}_{max}=\sqrt{{\left(\lambda k_{max}\right)}^2-\frac{l^2}{4} } \end{gathered}$$

$$\begin{gathered} X\mathrm{é}t \cos \left(\frac{∆\phi }{2}\right): \Rightarrow k \\ \Rightarrow I{O}_{min}=\sqrt{{\left(\lambda k_{min}\right)}^2-\frac{l^2}{4} },I{O}_{max}=\sqrt{{\left(\lambda k_{max}\right)}^2-\frac{l^2}{4} } \end{gathered}$$

$$\begin{gathered} S_{1}M<d<S_{1}I \\ \Rightarrow \frac{S_{1}M}{\lambda }<k+\frac{∆\phi }{4\pi }+0,5<\frac{S_{1}I}{\lambda } Khi \cos \left(\frac{{\phi }_2-{\phi }_1}{2}\right)>0 \\ \frac{S_{1}M}{\lambda }<k+\frac{∆\phi }{4\pi }<\frac{S_{1}I}{\lambda } Khi \cos \left(\frac{{\phi }_2-{\phi }_1}{2}\right)<0 \end{gathered}$$

$$\begin{gathered} S_{1}M<d<S_{1}I \\ \Rightarrow \frac{S_{1}M}{\lambda }<k+\frac{∆\phi }{4\pi }<\frac{S_{1}I}{\lambda } Khi \cos \left(\frac{{\phi }_2-{\phi }_1}{2}\right)>0 \\ \frac{S_{1}M}{\lambda }<k+\frac{∆\phi }{4\pi }+0,5<\frac{S_{1}I}{\lambda } Khi \cos \left(\frac{{\phi }_2-{\phi }_1}{2}\right)<0 \end{gathered}$$

$\frac{-S_1{S}_2}{\lambda }-\frac{{\phi }_2-{\phi }_1}{2\pi }-0,5<k<\frac{S_1{S}_2}{\lambda }-\frac{{\phi }_2-{\phi }_1}{2\pi }-0,5$

Với 2 nguồn cùng pha : số cực tiểu luôn chẵn

Với 2 nguồn ngược pha : số cực tiểu luôn lẻ

$\frac{-S_1{S}_2}{\lambda }-\frac{{\phi }_2-{\phi }_1}{2\pi }<k<\frac{S_1{S}_2}{\lambda }-\frac{{\phi }_2-{\phi }_1}{2\pi }$

Với 2 nguồn cùng pha : số cực đại luôn lẻ

Với 2 nguồn ngược pha : số cực đại luôn chẵn

$$\begin{gathered} \frac{\mathrm{\pi }\left({\mathrm{d}}_{2\mathrm{M}}-{\mathrm{d}}_{1\mathrm{M}}\right)}{\lambda }-\frac{{\phi }_2-{\phi }_1}{2}=\left(k\right)\pi \\ \Rightarrow ∆d_M=d_{2M}-d_{1M}=\left(k+\frac{{\phi }_2-{\phi }_1}{2\pi }\right)\lambda \end{gathered}$$

$$\begin{gathered} \frac{\mathrm{\pi }\left({\mathrm{d}}_{2\mathrm{M}}-{\mathrm{d}}_{1\mathrm{M}}\right)}{\lambda }-\frac{{\phi }_2-{\phi }_1}{2}=\left(k+\frac{1}{2}\right)\pi \\ \Rightarrow ∆d_M=d_{2M}-d_{1M}=\left(k+0,5+\frac{{\phi }_2-{\phi }_1}{2\pi }\right)\lambda \end{gathered}$$