Công thức vật lý - Vật Lý 24/7

$P=\frac{E}{t}=\frac{NQ}{t}=\frac{H.m.N_A.Q}{Mt}$

$D=\frac{3}{4\pi {\left(R_0\right)}^3}$ không đổi

$$\begin{gathered} N=\frac{k^n-1}{k-1} \\ sô notron \sin h: k^n \end{gathered}$$

${}_{Z_1}{}^{A_1}X_1+{}_{Z_2}{}^{A_2}X_2+\gamma \to {}_{Z_3}{}^{A_3}X_3+{}_{Z_4}{}^{A_4}X_4+Q$

$\Rightarrow E_{\gamma }=\left(m_{X_4}+m_{X_3}-m_{X_2}-m_{X_2}\right)c^2+Q$

$E_{\gamma }=hf$

$N_{thu}=\frac{s}{S}.∆N=\frac{s}{4\pi d^2}\left(1-e^{-\lambda t}\right)$

$V=\frac{H_1}{H_2}{e}^{-\lambda t}=\frac{N_1}{N_2}.2^{-\frac{t}{T}}.V_0$

$$\begin{gathered} \%h\mathrm{ạ}t đ\mathrm{ã} phân r\mathrm{ã}=(1-2^{\frac{-t}{T}}).100 \\ \% hat con lai =\left(2^{\frac{-t}{T}}\right)100 \end{gathered}$$

$\frac{m_{con}}{m_{me}}=\left(2^{t/T}-1\right)\frac{A_{con}}{A_{me}}$

$\frac{K_B}{A_C}=\frac{K_C}{A_B}=\frac{Q}{A_A}$